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A020491
Numbers k such that sigma_0(k) divides phi(k).
17
1, 3, 5, 7, 8, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 26, 28, 29, 30, 31, 33, 34, 35, 37, 39, 40, 41, 43, 45, 47, 49, 51, 52, 53, 55, 56, 57, 58, 59, 61, 63, 65, 67, 69, 70, 71, 72, 73, 74, 76, 77, 78, 79, 82, 83, 84, 85, 87, 88, 89, 90, 91, 93, 95, 97, 98, 99, 101, 102, 103, 104
OFFSET
1,2
COMMENTS
In other words, numbers k such that d(k) divides phi(k).
From Enrique Pérez Herrero, Aug 11 2010: (Start)
sigma_0(k) divides phi(k) when:
k is an odd prime: A065091;
k is an odd squarefree number: A056911;
k = 2^m, where m <> 1 is a Mersenne number (A000225).
If d divides (p-1), with p prime, then p^(d-1) is in this sequence, as are p^(p-1), p^(p-2) and p^(-1+p^n).
(End)
phi(n) and d(n) are multiplicative functions, so if m and n are coprime and both of them are in this sequence then m*n is also in this sequence. - Enrique Pérez Herrero, Sep 05 2010
From Bernard Schott, Aug 14 2020: (Start)
The corresponding quotients are in A289585.
About the 3rd case of Enrique Pérez Herrero's comment: if k = 2^M_m, where M_m = 2^m - 1 is a Mersenne number >= 3 (A000225), then the corresponding quotient phi(k)/d(k) is the integer 2^(2^m-m-2) = A076688(m); hence, these numbers k, A058891 \ {2}, form a subsequence. (End)
LINKS
Enrique Pérez Herrero, Table of n, a(n) for n = 1..5000
Psychedelic Geometry Blogspot, Fermat and Mersenne Numbers Conjecture-(2)
MATHEMATICA
Select[ Range[ 105 ], IntegerQ[ EulerPhi[ # ]/DivisorSigma[ 0, # ] ]& ]
PROG
(PARI) isok(k) = !(eulerphi(k) % numdiv(k)); \\ Michel Marcus, Aug 10 2020
CROSSREFS
Complement of A015733. [Enrique Pérez Herrero, Aug 11 2010]
Sequence in context: A141114 A136443 A247459 * A168501 A173186 A335575
KEYWORD
nonn
STATUS
approved