Solution Manual for Engineering Mechanics Dynamics 2nd Edition by Tongue. Full file at https... more Solution Manual for Engineering Mechanics Dynamics 2nd Edition by Tongue. Full file at https://testbanku.eu/
1.1 Using the definition of acceleration: α = ∆v ∆t − 60 mph − 0 9.2 − 0 = 88 ft/sec − 0 9.2 sec ... more 1.1 Using the definition of acceleration: α = ∆v ∆t − 60 mph − 0 9.2 − 0 = 88 ft/sec − 0 9.2 sec = 9.57 ft/sec 2 1.2 Differentiate x(t) to obtain the velocity: v(t) = ˙ x(t) = −10t + 88 ft/sec. Differentiating again yields the acceleration: a(t) = ¨ x(t) = −10 ft/sec 2. So v(t) = 0 = −10t + 88. Solving this for t yields that: v(t) = 0 at t = 8.8 sec. 1.3 Evaluating x at zero yields x(0) = 5 m. Differentiating yields ˙ x(t) = v(t) = 3t 2 − 2 so that v(0) = −2 m/s. Likewise a(t) = ¨ x(t) = 6t so that a(0) = 0. Now at t = 3 sec, x(3) = 27 − 2(3) + 5 = 26 m, v(3) = 27 − 2 = 25 m/s and a(3) = 18 m/s 2. Since the velocity changes sign during this interval, the particle has doubled back and to compute the total distance traveled during the interval you must compute how far it travels before it changes direction and then add this to the distance traveled after the particle has changed direction. The particle changes direction when the velocity is zero, or at the value of t for which v(t) = 3t 2 − 2 = 0, or at time t = 0.8165. The particle first moves from x(0) = 5 m to x(0.8165) = 3.9 m or a distance of 1.1 m.Solution Manual for Engineering Mechanics Dynamics 1st Edition by Soutas Little. Full file at https://testbanku.eu/
Solution Manual for Engineering Mechanics Dynamics 13th Edition by Hibbeler. Full file at ht... more Solution Manual for Engineering Mechanics Dynamics 13th Edition by Hibbeler. Full file at https://testbanku.eu/
Solution Manual for Engineering Management Challenges in the New Millennium by Chang Complete dow... more Solution Manual for Engineering Management Challenges in the New Millennium by Chang Complete downloadable file at: https://testbanku. Full file at https://testbanku.eu/
Solution Manual for Engineering Fluid Mechanics 11th Edition by Elger. Full file at https://... more Solution Manual for Engineering Fluid Mechanics 11th Edition by Elger. Full file at https://testbanku.eu/
Solution Manual for Engineering Fluid Mechanics 10th Edition by Elger. Full file at https://... more Solution Manual for Engineering Fluid Mechanics 10th Edition by Elger. Full file at https://testbanku.eu/
Solution Manual for Engineering Mechanics Dynamics 2nd Edition by Tongue. Full file at https... more Solution Manual for Engineering Mechanics Dynamics 2nd Edition by Tongue. Full file at https://testbanku.eu/
1.1 Using the definition of acceleration: α = ∆v ∆t − 60 mph − 0 9.2 − 0 = 88 ft/sec − 0 9.2 sec ... more 1.1 Using the definition of acceleration: α = ∆v ∆t − 60 mph − 0 9.2 − 0 = 88 ft/sec − 0 9.2 sec = 9.57 ft/sec 2 1.2 Differentiate x(t) to obtain the velocity: v(t) = ˙ x(t) = −10t + 88 ft/sec. Differentiating again yields the acceleration: a(t) = ¨ x(t) = −10 ft/sec 2. So v(t) = 0 = −10t + 88. Solving this for t yields that: v(t) = 0 at t = 8.8 sec. 1.3 Evaluating x at zero yields x(0) = 5 m. Differentiating yields ˙ x(t) = v(t) = 3t 2 − 2 so that v(0) = −2 m/s. Likewise a(t) = ¨ x(t) = 6t so that a(0) = 0. Now at t = 3 sec, x(3) = 27 − 2(3) + 5 = 26 m, v(3) = 27 − 2 = 25 m/s and a(3) = 18 m/s 2. Since the velocity changes sign during this interval, the particle has doubled back and to compute the total distance traveled during the interval you must compute how far it travels before it changes direction and then add this to the distance traveled after the particle has changed direction. The particle changes direction when the velocity is zero, or at the value of t for which v(t) = 3t 2 − 2 = 0, or at time t = 0.8165. The particle first moves from x(0) = 5 m to x(0.8165) = 3.9 m or a distance of 1.1 m.Solution Manual for Engineering Mechanics Dynamics 1st Edition by Soutas Little. Full file at https://testbanku.eu/
Solution Manual for Engineering Mechanics Dynamics 13th Edition by Hibbeler. Full file at ht... more Solution Manual for Engineering Mechanics Dynamics 13th Edition by Hibbeler. Full file at https://testbanku.eu/
Solution Manual for Engineering Management Challenges in the New Millennium by Chang Complete dow... more Solution Manual for Engineering Management Challenges in the New Millennium by Chang Complete downloadable file at: https://testbanku. Full file at https://testbanku.eu/
Solution Manual for Engineering Fluid Mechanics 11th Edition by Elger. Full file at https://... more Solution Manual for Engineering Fluid Mechanics 11th Edition by Elger. Full file at https://testbanku.eu/
Solution Manual for Engineering Fluid Mechanics 10th Edition by Elger. Full file at https://... more Solution Manual for Engineering Fluid Mechanics 10th Edition by Elger. Full file at https://testbanku.eu/
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