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‎1-Select/1148_Article_Views_I.sql

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-- Source: https://leetcode.com/problems/article-views-i/description/?envType=study-plan-v2&envId=top-sql-50
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-- Table: Views
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-- +---------------+---------+
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-- | Column Name | Type |
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-- +---------------+---------+
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-- | article_id | int |
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-- | author_id | int |
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-- | viewer_id | int |
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-- | view_date | date |
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-- +---------------+---------+
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-- There is no primary key (column with unique values) for this table, the table may have duplicate rows.
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-- Each row of this table indicates that some viewer viewed an article (written by some author) on some date.
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-- Note that equal author_id and viewer_id indicate the same person.
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-- Write a solution to find all the authors that viewed at least one of their own articles.
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-- Return the result table sorted by id in ascending order.
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------------------------------------------------------------------------------
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-- SQL Schema
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CREATE TABLE IF NOT EXISTS Views (article_id int, author_id int, viewer_id int, view_date date)
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TRUNCATE TABLE Views
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('1', '3', '5', '2019-08-01')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('1', '3', '6', '2019-08-02')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('2', '7', '7', '2019-08-01')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('2', '7', '6', '2019-08-02')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('4', '7', '1', '2019-07-22')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('3', '4', '4', '2019-07-21')
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INSERT INTO Views (article_id, author_id, viewer_id, view_date) VALUES ('3', '4', '4', '2019-07-21')
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-- MS SQL Server Code
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SELECT DISTINCT author_id AS 'id'
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FROM Views
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WHERE author_id = viewer_id
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ORDER BY 1 ASC

‎1-Select/1683_Invalid_Tweets.sql

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-- Source: https://leetcode.com/problems/invalid-tweets/description/?envType=study-plan-v2&envId=top-sql-50
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-- Table: Tweets
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-- +----------------+---------+
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-- | Column Name | Type |
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-- +----------------+---------+
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-- | tweet_id | int |
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-- | content | varchar |
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-- +----------------+---------+
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-- tweet_id is the primary key (column with unique values) for this table.
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-- This table contains all the tweets in a social media app.
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-- Write a solution to find the IDs of the invalid tweets. The tweet is invalid if the number of characters used in the content of the tweet is strictly greater than 15.
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-- Return the result table in any order.
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------------------------------------------------------------------------------
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-- SQL Schema
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CREATE TABLE IF NOT EXISTS Tweets(tweet_id int, content varchar(50))
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TRUNCATE TABLE Tweets
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INSERT INTO Tweets (tweet_id, content) VALUES ('1', 'Vote for Biden')
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INSERT INTO Tweets (tweet_id, content) VALUES ('2', 'Let us make America great again!')
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-- MS SQL Server Code
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SELECT tweet_id
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FROM Tweets
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WHERE LEN(content) > 15

‎1-Select/1757_Recyclable_and_Low_Fat_Products.sql

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-- Source: https://leetcode.com/problems/recyclable-and-low-fat-products/description/?envType=study-plan-v2&envId=top-sql-50
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-- Table: Products
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-- +-------------+---------+
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-- | Column Name | Type |
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-- +-------------+---------+
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-- | product_id | int |
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-- | low_fats | enum |
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-- | recyclable | enum |
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-- +-------------+---------+
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-- product_id is the primary key (column with unique values) for this table.
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-- low_fats is an ENUM (category) of type ('Y', 'N') where 'Y' means this product is low fat and 'N' means it is not.
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-- recyclable is an ENUM (category) of types ('Y', 'N') where 'Y' means this product is recyclable and 'N' means it is not.
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-- Write a solution to find the ids of products that are both low fat and recyclable.
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-- Return the result table in any order.
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------------------------------------------------------------------------------
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-- SQL Schema
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CREATE TABLE IF NOT EXISTS Products (product_id int, low_fats ENUM('Y', 'N'), recyclable ENUM('Y','N'))
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TRUNCATE TABLE Products
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INSERT INTO Products (product_id, low_fats, recyclable) VALUES ('0', 'Y', 'N')
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INSERT INTO Products (product_id, low_fats, recyclable) VALUES ('1', 'Y', 'Y')
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INSERT INTO Products (product_id, low_fats, recyclable) VALUES ('2', 'N', 'Y')
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INSERT INTO Products (product_id, low_fats, recyclable) VALUES ('3', 'Y', 'Y')
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INSERT INTO Products (product_id, low_fats, recyclable) VALUES ('4', 'N', 'N')
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-- MS SQL Server Code
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SELECT product_id
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FROM Products
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WHERE low_fats = 'Y' AND recyclable = 'Y'

‎1-Select/584_Find_Customer_Referee.sql

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-- Source: https://leetcode.com/problems/find-customer-referee/description/?envType=study-plan-v2&envId=top-sql-50
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-- Table: Customer
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-- +-------------+---------+
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-- | Column Name | Type |
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-- +-------------+---------+
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-- | id | int |
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-- | name | varchar |
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-- | referee_id | int |
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-- +-------------+---------+
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-- In SQL, id is the primary key column for this table.
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-- Each row of this table indicates the id of a customer, their name, and the id of the customer who referred them.
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-- Find the names of the customer that are not referred by the customer with id = 2.
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-- Return the result table in any order.
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-- The result format is in the following example.
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------------------------------------------------------------------------------
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-- SQL Schema
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CREATE TABLE IF NOT EXISTS Customer (id int, name varchar(25), referee_id int)
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TRUNCATE TABLE Customer
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INSERT INTO Customer (id, name, referee_id) VALUES ('1', 'Will', 'None')
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INSERT INTO Customer (id, name, referee_id) VALUES ('2', 'Jane', 'None')
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INSERT INTO Customer (id, name, referee_id) VALUES ('3', 'Alex', '2')
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INSERT INTO Customer (id, name, referee_id) VALUES ('4', 'Bill', 'None')
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INSERT INTO Customer (id, name, referee_id) VALUES ('5', 'Zack', '1')
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INSERT INTO Customer (id, name, referee_id) VALUES ('6', 'Mark', '2')
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-- MS SQL Server Code
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SELECT name
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FROM Customer
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WHERE referee_id <> 2 OR referee_id IS NULL

‎1-Select/595_Big_Countries.sql

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-- Source: https://leetcode.com/problems/big-countries/description/?envType=study-plan-v2&envId=top-sql-50
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-- Table: World
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-- +-------------+---------+
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-- | Column Name | Type |
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-- +-------------+---------+
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-- | name | varchar |
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-- | continent | varchar |
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-- | area | int |
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-- | population | int |
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-- | gdp | bigint |
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-- +-------------+---------+
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-- name is the primary key (column with unique values) for this table.
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-- Each row of this table gives information about the name of a country, the continent to which it belongs, its area, the population, and its GDP value.
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-- A country is big if:
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-- it has an area of at least three million (i.e., 3000000 km2), or
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-- it has a population of at least twenty-five million (i.e., 25000000).
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-- Write a solution to find the name, population, and area of the big countries.
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-- Return the result table in any order.
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------------------------------------------------------------------------------
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-- SQL Schema
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CREATE TABLE IF NOT EXISTS World (name varchar(255), continent varchar(255), area int, population int, gdp bigint)
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TRUNCATE TABLE World
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INSERT INTO World (name, continent, area, population, gdp) VALUES ('Afghanistan', 'Asia', '652230', '25500100', '20343000000')
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INSERT INTO World (name, continent, area, population, gdp) VALUES ('Albania', ' 6CB7 Europe', '28748', '2831741', '12960000000')
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INSERT INTO World (name, continent, area, population, gdp) VALUES ('Algeria', 'Africa', '2381741', '37100000', '188681000000')
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INSERT INTO World (name, continent, area, population, gdp) VALUES ('Andorra', 'Europe', '468', '78115', '3712000000')
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INSERT INTO World (name, continent, area, population, gdp) VALUES ('Angola', 'Africa', '1246700', '20609294', '100990000000')
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-- MS SQL Server Code
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SELECT name, population, area
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FROM World
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WHERE area >= 3000000 OR population >= 25000000

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