Replies: 2 comments 2 replies
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You can try this: >>> V = '0\xca\xfa\xd6A'
>>> B = bytes([ord(i) for i in V])
>>> V
'0\xca\xfa\xd6A'
>>> B
b'0\xca\xfa\xd6A'
>>> |
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Wow, |
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A possibly slight neater idiom might be: Since |
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Nice! |
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Good morning Forum,
I want to decrypt (AES encryption) a string e.g. '0\xca\xfa\xd6A\x89\xab ...'
Now I write this string into a variable VAR
To convert this string into blocks with a b in front of the string: VAR=b'0\xca\xfa\xd6A\x89\xab ...'
That works.
Now I have a string variable VAR='0\xca\xfa\xd6A\x89\xab ...' (without b in front)
I convert this VAR into blocks like this: VAR = bytes(VAR, 'utf-8')
I get the b in front of VAR, but now I get a double backslash instead of this single backslash in VAR
How is it possible to set this b sign in front of VAR with single backslash in VAR?
Thanks a lot for a tip
Klaus
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