8000 lenght of a masked array? (Trac #1181) · Issue #1779 · numpy/numpy · GitHub
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thouis opened this issue Oct 19, 2012 · 2 comments
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lenght of a masked array? (Trac #1181) #1779

thouis opened this issue Oct 19, 2012 · 2 comments
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01 - Enhancement component: Other

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@thouis
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thouis commented Oct 19, 2012

Original ticket http://projects.scipy.org/numpy/ticket/1181 on 2009-07-23 by @dalloliogm, assigned to unknown.

What should len() of a masked array return?

If I mask an array, I would expect that its lenght is equal to the number of not-masked elements, or at least I would like to have a function to retrieve such information.

>>> import numpy
>>> m = numpy.ma.masked_equal([1, 2, None, 3, None, None, 4], None)

I would expect len(m) to be 4
>>> len(m)
7

There is not an alternative function as for average, var, for masked arrays:
>>> numpy.ma.average(m)
2
>>> numpy.average(m)
TypeError

>>> numpy.ma.len(m)
Function doesn't exists
@thouis
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thouis commented Oct 19, 2012

@dalloliogm wrote on 2009-08-03

Sorry, the function is masked_array.count().

@thouis
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thouis commented Oct 19, 2012

@pierregm wrote on 2010-02-14

Use .count to get the nb of unmasked elements.

@thouis thouis closed this as completed Oct 19, 2012
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