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Source : https://oj.leetcode.com/problems/path-sum/","// Author : Hao Chen","// Date : 2014-06-22","","/********************************************************************************** ","* ","* Given a binary tree and a sum, determine if the tree has a root-to-leaf path ","* such that adding up all the values along the path equals the given sum.","* ","* For example:","* Given the below binary tree and sum = 22,","* ","* 5","* / \\","* 4 8","* / / \\","* 11 13 4","* / \\ \\","* 7 2 1","* ","* return true, as there exist a root-to-leaf path 5-\u003e4-\u003e11-\u003e2 which sum is 22.","* ","**********************************************************************************/","","#include \u003ctime.h\u003e","","/**"," * Definition for binary tree"," * struct TreeNode {"," * int val;"," * TreeNode *left;"," * TreeNode *right;"," * TreeNode(int x) : val(x), left(NULL), right(NULL) {}"," * };"," */","class Solution {","public:"," Solution(){"," srand(time(NULL));"," }"," bool hasPathSum(TreeNode *root, int sum) {"," if (random()%2){"," return hasPathSum1(root, sum); "," }"," return hasPathSum2(root, sum);"," }"," "," bool hasPathSum1(TreeNode *root, int sum) {"," if (root==NULL) return false;"," vector\u003cTreeNode*\u003e v;"," v.push_back(root);"," while(v.size()\u003e0){"," TreeNode* node = v.back();"," v.pop_back();"," if (node-\u003eleft==NULL \u0026\u0026 node-\u003eright==NULL){"," if (node-\u003eval == sum){"," return true;"," }"," }"," if (node-\u003eleft){"," node-\u003eleft-\u003eval += node-\u003eval;"," v.push_back(node-\u003eleft);"," }"," if (node-\u003eright){"," node-\u003eright-\u003eval += node-\u003eval;"," v.push_back(node-\u003eright);"," }"," }"," return false;"," "," }"," "," bool hasPathSum2(TreeNode *root, int sum) {"," "," if (root==NULL) return false;"," "," if (root-\u003eleft==NULL \u0026\u0026 root-\u003eright==NULL ){"," return (root-\u003eval==sum);"," }"," "," if (root-\u003eleft){"," root-\u003eleft-\u003eval += root-\u003eval;"," if (hasPathSum2(root-\u003eleft, sum)){"," return true;"," }"," }"," "," if (root-\u003eright){"," root-\u003eright-\u003eval += root-\u003eval;"," if (hasPathSum2(root-\u003eright, sum)){"," return true;"," }"," }"," "," return false;"," 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