8000 Refactoring to convert && chain to optional chain expression · Issue #35018 · microsoft/TypeScript · GitHub
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Refactoring to convert && chain to optional chain expression #35018
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#39135
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Refactoring to convert && chain to optional chain expression#35018
#39135
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minestarksjessetrinity
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CommittedThe team has roadmapped this issueDomain: Refactoringse.g. extract to constant or function, rename symbolFix AvailableA PR has been opened for this issueSuggestionAn idea for TypeScript
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TypeScript 4.0.1
@DanielRosenwasser

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@DanielRosenwasser
DanielRosenwasser
opened on Nov 9, 2019
interface Foo {
    bar?: {
        baz?: string;
    }
}

declare let foo: Foo | undefined;

[|foo && foo.bar && foo.bar.baz|]

It should be possible to convert that chain into the following:

interface Foo {
    bar?: {
        baz?: string;
    }
}

declare let foo: Foo | undefined;

foo?.bar?.baz;

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CommittedThe team has roadmapped this issueDomain: Refactoringse.g. extract to constant or function, rename symbolFix AvailableA PR has been opened for this issueSuggestionAn idea for TypeScript

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