Bank Accounts Summary II

SQL SChema

Create table If Not Exists Users (account int, name varchar(20));
Create table If Not Exists Transactions (trans_id int, account int, amount int, transacted_on date);
Truncate table Users;
insert into Users (account, name) values ('900001', 'Alice');
insert into Users (account, name) values ('900002', 'Bob');
insert into Users (account, name) values ('900003', 'Charlie');
Truncate table Transactions;
insert into Transactions (trans_id, account, amount, transacted_on) values ('1', '900001', '7000', '2020-08-01');
insert into Transactions (trans_id, account, amount, transacted_on) values ('2', '900001', '7000', '2020-09-01');
insert into Transactions (trans_id, account, amount, transacted_on) values ('3', '900001', '-3000', '2020-09-02');
insert into Transactions (trans_id, account, amount, transacted_on) values ('4', '900002', '1000', '2020-09-12');
insert into Transactions (trans_id, account, amount, transacted_on) values ('5', '900003', '6000', '2020-08-07');
insert into Transactions (trans_id, account, amount, transacted_on) values ('6', '900003', '6000', '2020-09-07');
insert into Transactions (trans_id, account, amount, transacted_on) values ('7', '900003', '-4000', '2020-09-11');

Table: Users

+--------------+---------+
| Column Name  | Type    |
+--------------+---------+
| account      | int     |
| name         | varchar |
+--------------+---------+
account is the primary key for this table.
Each row of this table contains the account number of each user in the bank.
There will be no two users having the same name in the table.

Table: Transactions

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| trans_id      | int     |
| account       | int     |
| amount        | int     |
| transacted_on | date    |
+---------------+---------+
trans_id is the primary key for this table.
Each row of this table contains all changes made to all accounts.
amount is positive if the user received money and negative if they transferred money.
All accounts start with a balance of 0.

Write an SQL query to report the name and balance of users with a balance higher than 10000. The balance of an account is equal to the sum of the amounts of all transactions involving that account.

Return the result table in any order.

The query result format is in the following example.

Example 1:

Input: 
Users table:
+------------+--------------+
| account    | name         |
+------------+--------------+
| 900001     | Alice        |
| 900002     | Bob          |
| 900003     | Charlie      |
+------------+--------------+
Transactions table:
+------------+------------+------------+---------------+
| trans_id   | account    | amount     | transacted_on |
+------------+------------+------------+---------------+
| 1          | 900001     | 7000       |  2020-08-01   |
| 2          | 900001     | 7000       |  2020-09-01   |
| 3          | 900001     | -3000      |  2020-09-02   |
| 4          | 900002     | 1000       |  2020-09-12   |
| 5          | 900003     | 6000       |  2020-08-07   |
| 6          | 900003     | 6000       |  2020-09-07   |
| 7          | 900003     | -4000      |  2020-09-11   |
+------------+------------+------------+---------------+
Output: 
+------------+------------+
| name       | balance    |
+------------+------------+
| Alice      | 11000      |
+------------+------------+
Explanation: 
Alice's balance is (7000 + 7000 - 3000) = 11000.
Bob's balance is 1000.
Charlie's balance is (6000 + 6000 - 4000) = 8000.

Solution

select Users.name, 
       sum(Transactions.amount) as balance
from Users
inner join Transactions
on Users.account = Transactions.account
group by Users.name
having(balance >= 10000)

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