add : 620

h-j-13 · h-j-13 · commit 82dd2cd4642a · 2017-12-11T16:05:33.000+08:00
diff --git a/Soulution/LeetCode 620. Not Boring Movies.md b/Soulution/LeetCode 620. Not Boring Movies.md
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+
+# LeetCode   620. Not Boring Movies
+## 题目
+X city opened a new ```cinema```, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions.
+
+Please write a SQL query to output movies with an odd numbered ID and a description that is not 'boring'. Order the result by rating.
+
+For example, table cinema:
+```
++---------+-----------+--------------+-----------+
+|   id    | movie     |  description |  rating   |
++---------+-----------+--------------+-----------+
+|   1     | War       |   great 3D   |   8.9     |
+|   2     | Science   |   fiction    |   8.5     |
+|   3     | irish     |   boring     |   6.2     |
+|   4     | Ice song  |   Fantacy    |   8.6     |
+|   5     | House card|   Interesting|   9.1     |
++---------+-----------+--------------+-----------+
+```
+For the example above, the output should be:
+```
++---------+-----------+--------------+-----------+
+|   id    | movie     |  description |  rating   |
++---------+-----------+--------------+-----------+
+|   5     | House card|   Interesting|   9.1     |
+|   1     | War       |   great 3D   |   8.9     |
++---------+-----------+--------------+-----------+
+```
+题目大意:请输入一个SQL查询来输出带有奇数编号的ID和不是“无聊”的描述。按等级排序结果。
+
+## 解题思路
+直接写SQL 就好了
+奇数用对2取余为1来表示即可
+
+```SQL
+SELECT * FROM cinema WHERE id % 2 = 1 AND description != 'boring' ORDER BY rating DESC  
+```
+
+发现也可以这样表示取余
+```sql
+select * from cinema where mod(id, 2) = 1 and description != 'boring' order by rating DESC  
+```
+
+
+
