erjan
diff --git a/‎3136. Valid Word.py
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+'''
+A word is considered valid if:
+
+It contains a minimum of 3 characters.
+It contains only digits (0-9), and English letters (uppercase and lowercase).
+It includes at least one vowel.
+It includes at least one consonant.
+You are given a string word.
+
+Return true if word is valid, otherwise, return false.
+
+Notes:
+
+'a', 'e', 'i', 'o', 'u', and their uppercases are vowels.
+A consonant is an English letter that is not a vowel.
+'''
+
+class Solution:
+    def isValid(self, word: str) -> bool:
+        vowels = 'aeiou'
+
+        word = word.lower()
+        cond1 = any(ch in vowels for ch in word)
+        cond2 = any(ch not in vowels and ch.isalpha() for ch in word)
+
+        cond4 = len(word)>=3
+
+        cond5 = all(ch.isdigit() or ch.isalpha() for ch in word)
+
+        return cond1 and cond2 and cond4 and cond5
+
+----------------------------------
+#regex
+
+class Solution:
+    def isValid(self, w: str) -> bool:
+        return match('^(?=.*[aeiou])(?=.*[^0-9aeiou])[a-z0-9]{3,}$',w,I)
+
+------------------------------------------------------------------------------------
+
+
+
+class Solution:
+    def isValid(self, word: str) -> bool:
+        if len(word) < 3:
+            return False
+        
+        vowelcount = 0
+        consonantcount = 0
+        validcharacterscount = 0
+        vowels = "aeiou"
+        
+        for char in word:
+            if char.isalpha():
+                if char.lower() in vowels:
+                    vowelcount += 1
+                else:
+                    consonantcount += 1
+                validcharacterscount += 1
+            elif char.isdigit():
+                validcharacterscount += 1
+            else:
+                return False
+        
+        # Check if it meets all criteria
+        return validcharacterscount >= 3 and vowelcount >= 1 and consonantcount >= 1