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Source : https://oj.leetcode.com/problems/triangle/","// Author : Hao Chen","// Date : 2014-06-18","","/********************************************************************************** ","* ","* Given a triangle, find the minimum path sum from top to bottom. ","* Each step you may move to adjacent numbers on the row below.","* ","* For example, given the following triangle","* ","* [","* [2],","* [3,4],","* [6,5,7],","* [4,1,8,3]","* ]","* ","* The minimum path sum from top to bottom is 11 (i.e., 2 + 3 + 5 + 1 = 11).","* ","* Note:","* Bonus point if you are able to do this using only O(n) extra space, where n is the total number of rows in the triangle.","* ","* ","**********************************************************************************/","","#include \u003ciostream\u003e","#include \u003cvector\u003e","using namespace std;","","class Solution {"," ","public:"," int minimumTotal(vector\u003cvector\u003cint\u003e \u003e \u0026triangle) {"," vector\u003c vector\u003cint\u003e \u003e v;"," "," for (int i=0; i\u003ctriangle.size(); i++){"," "," if(i==0){"," v.push_back(triangle[i]);"," continue;"," }"," "," vector\u003cint\u003e tmp;"," "," "," for(int j=0; j\u003ctriangle[i].size(); j++){"," int x, y, z;"," x = y = z = 0x7fff;"," if ( (j-1) \u003e= 0){"," x = v[i-1][j-1];"," }"," if (j\u003cv[i-1].size()) {"," y = v[i-1][j];"," }"," /* won't take the previous adjacent number */"," //if ( (j+1)\u003cv[i-1].size()) {"," // z = v[i-1][j+1];"," //}"," tmp.push_back( min(x,y,z) + triangle[i][j] );"," }"," "," v.push_back(tmp);"," "," }"," int min=0x7fff;"," if (v.size() \u003e 0){"," vector\u003cint\u003e \u0026vb = v[v.size()-1];"," for(int i=0; i\u003cvb.size(); i++){"," if (vb[i] \u003c min ){"," min = vb[i];"," }"," }"," }"," "," return min;"," }","private:"," inline int min(int x, int y, int z){"," int n = x\u003cy?x:y;"," return (n\u003cz?n:z);"," }","};","","","int main()","{"," vector\u003c vector\u003cint\u003e \u003e v;"," vector\u003cint\u003e i;"," i.push_back(-1);"," v.push_back(i);"," "," i.clear();"," i.push_back(2);"," i.push_back(3);"," v.push_back(i);",""," i.clear();"," i.push_back(1);"," i.push_back(-1);"," i.push_back(-3);"," v.push_back(i);",""," Solution s;"," cout \u003c\u003c s.minimumTotal(v) \u003c\u003c endl;;"," "," v.clear();"," i.clear();"," i.push_back(-1);"," v.push_back(i);"," "," i.clear();"," i.push_back(3);"," i.push_back(2);"," v.push_back(i);",""," i.clear();"," i.push_back(-3);"," i.push_back(1);"," i.push_back(-1);"," v.push_back(i);"," cout \u003c\u003c s.minimumTotal(v) \u003c\u003c endl;;",""," return 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