Feat: #176

FX-Max · FX-Max · commit 59985f8c4acf · 2021-01-25T02:10:21.000+08:00
Close:#176
diff --git a/problems/database/176.md b/problems/database/176.md
@@ -5,7 +5,7 @@
 需要找出表中第二高的薪水，可以考虑先找出最高的薪水，再从表中找出小于最高薪水剩余部分中最高的薪水，即为第二高薪水。
 
 ## 代码
-```
+```sql
 # Write your MySQL query statement below
 select max(e1.Salary) as SecondHighestSalary
 from Employee e1
