1856 United States presidential election in Illinois
(Redirected from United States presidential election in Illinois, 1856)
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 County Results
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| Elections in Illinois |
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The 1856 United States presidential election in Illinois took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 11 representatives, or electors to the Electoral College, who voted for president and vice president.
Illinois voted for the Democratic candidate, James Buchanan, over Republican candidate John C. Frémont and American Party candidate Millard Fillmore. Buchanan won Illinois by a narrow margin of 3.86%.
This would be the final time a Democratic presidential candidate would win Illinois until Grover Cleveland won it in 1892.
Results
[edit]| 1856 United States presidential election in Illinois[1][2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 105,528 | 44.09% | 11 | 100.00% | ||
| Republican | John C. Frémont of California | William L. Dayton of New Jersey | 96,275 | 40.23% | 0 | 0.00% | ||
| Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 37,531 | 15.68% | 0 | 0.00% | ||
| Total | 239,334 | 100.00% | 11 | 100.00% | ||||
See also
[edit]References
[edit]- ^ "1856 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved December 3, 2017.
- ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.
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